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Last updated: October 19. 2013 4:36PM - 507 Views
Associated Press



Denmark's Caroline Wozniacki returns the ball towards Germany's Sabine Lisicki, during the semi finals of the Luxembourg Open 2013, in Kockelscheuer, Luxembourg, Saturday Oct. 19, 2013. (AP Photo/Yves Logghe)
Denmark's Caroline Wozniacki returns the ball towards Germany's Sabine Lisicki, during the semi finals of the Luxembourg Open 2013, in Kockelscheuer, Luxembourg, Saturday Oct. 19, 2013. (AP Photo/Yves Logghe)
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(AP) Top-seeded Caroline Wozniacki of Denmark will play Annika Beck of Germany in Sunday's final of the Luxembourg Open.


Wozniacki, ranked No. 9, defeated third-seeded Sabine Lisicki of Germany 6-4, 6-4 in Saturday's semifinals. She has lost only one set all week.


Beck advanced to her first WTA final when Stefanie Voegele of Switzerland retired at 7-5, 1-0 in the other semi.


Wozniacki has 20 career titles but yet to win one this year. She and Beck will meet for the first time.


Associated Press
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